# PWN the SAT Q&A

Anonymous

Question for now that I have been really confused about lately. Say you have two spinners, spinner 1 and spinner 2. Spinner 1 has numbers 1-4 and spinner 2 has numbers 1-6. You are trying to find the number of pairs that have a sum that is at least 8. We will use order (spinner 1, spinner 2). But you can get (4,4) on both spinners. Now, theoretically if you were to change the order (spinner 1:4, spinner 2:4) to (spinner 2:4, spinner 1:4) wouldn't that be 2? Could you ever do that ?

Good question. What you want to do for something like this is list out ALL the possible results. That’ll help you see what’s really going on:

1,1    1,2    1,3    1,4

2,1    2,2    2,3    2,4

3,1    3,2    3,3    3,4

4,1    4,2    4,3    4,4

5,1    5,2    5,3    5,4

6,1    6,2    6,3    6,4

I’ve bolded the number of outcomes that sum to at least 8. There are 6 of them.

This is confusing, right? The question you’re asking is a common question people ask when they’re learning probability with dice, too. The best way to learn it, I think, is to see it all laid out for you like above. There’s only one way to get 4,4—both spinners have to be 4. There aren’t 2 ways for both spinners to be 4.

Does that help?